From 6e3475e4050d9dbf64f83af62388d91708dc43f1 Mon Sep 17 00:00:00 2001
From: Mark Pilgrim <mark@diveintomark.org>
Date: Mon, 11 Jan 2010 17:38:22 -0500
Subject: [PATCH] typo [thanks GG]

---
 strings.html | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/strings.html b/strings.html
index f909fe5..edc98c7 100755
--- a/strings.html
+++ b/strings.html
@@ -261,7 +261,7 @@ experience of years.</samp>
 <samp class=pp>{'password': 'PapayaWhip', 'user': 'pilgrim', 'database': 'master'}</samp></pre>
 
 <ol>
-<li>The <code><dfn>split</dfn>()</code> string method takes one argument, a delimiter, and split a string into a list of strings based on the delimiter. Here, the delimiter is an ampersand character, but it could be anything.
+<li>The <code><dfn>split</dfn>()</code> string method takes one argument, a delimiter, and splits a string into a list of strings based on the delimiter. Here, the delimiter is an ampersand character, but it could be anything.
 <li>Now we have a list of strings, each with a key, followed by an equals sign, followed by a value. We can use a <a href=comprehensions.html#listcomprehension>list comprehension</a> to iterate over the entire list and split each string into two strings based on the first equals sign. (In theory, a value could contain an equals sign too. If we just used <code>'key=value=foo'.split('=')</code>, we would end up with a three-item list <code>['key', 'value', 'foo']</code>.)
 <li>Finally, Python can turn that list-of-lists into a dictionary simply by passing it to the <code>dict()</code> function.
 </ol>