fix #2247

We have to pass urllib3 the url without the authentication information,
else it will be parsed by httplib as a netloc and included in the request line
and Host header

requests/adapters.py

@@ -17,7 +17,7 @@ from .packages.urllib3.response import HTTPResponse
 from .packages.urllib3.util import Timeout as TimeoutSauce
 from .compat import urlparse, basestring, urldefrag
 from .utils import (DEFAULT_CA_BUNDLE_PATH, get_encoding_from_headers,
-                    prepend_scheme_if_needed, get_auth_from_url)
+                    prepend_scheme_if_needed, get_auth_from_url, urldefragauth)
 from .structures import CaseInsensitiveDict
 from .packages.urllib3.exceptions import ConnectTimeoutError
 from .packages.urllib3.exceptions import HTTPError as _HTTPError
@@ -270,7 +270,7 @@ class HTTPAdapter(BaseAdapter):
         proxy = proxies.get(scheme)
 
         if proxy and scheme != 'https':
-            url, _ = urldefrag(request.url)
+            url = urldefragauth(request.url)
         else:
             url = request.path_url
 

requests/utils.py

@@ -672,3 +672,18 @@ def to_native_string(string, encoding='ascii'):
             out = string.decode(encoding)
 
     return out
+
+
+def urldefragauth(url):
+    """
+    Given a url remove the fragment and the authentication part
+    """
+    scheme, netloc, path, params, query, fragment = urlparse(url)
+
+    # see func:`prepend_scheme_if_needed`
+    if not netloc:
+        netloc, path = path, netloc
+
+    netloc = netloc.rsplit('@', 1)[-1]
+
+    return urlunparse((scheme, netloc, path, params, query, ''))